4x^2+96x-664=0

Solution for 4x^2+96x-664=0 equation:

4x^2+96x-664=0

a = 4; b = 96; c = -664;
Δ = b2-4ac
Δ = 962-4·4·(-664)
Δ = 19840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{19840}=\sqrt{64*310}=\sqrt{64}*\sqrt{310}=8\sqrt{310}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-8\sqrt{310}}{2*4}=\frac{-96-8\sqrt{310}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+8\sqrt{310}}{2*4}=\frac{-96+8\sqrt{310}}{8}
$